0=-4.9x^2+26x+0.25

Solution for 0=-4.9x^2+26x+0.25 equation:

0=-4.9x^2+26x+0.25

We move all terms to the left:

0-(-4.9x^2+26x+0.25)=0

We add all the numbers together, and all the variables

-(-4.9x^2+26x+0.25)=0

We get rid of parentheses

4.9x^2-26x-0.25=0

a = 4.9; b = -26; c = -0.25;
Δ = b2-4ac
Δ = -262-4·4.9·(-0.25)
Δ = 680.9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-\sqrt{680.9}}{2*4.9}=\frac{26-\sqrt{680.9}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+\sqrt{680.9}}{2*4.9}=\frac{26+\sqrt{680.9}}{9.8}
$